- Published on
How Many Numbers Are Smaller Than the Current Number
- Authors
- Name
- ShoxruxC
- @iOSdasturchi
📝 Vazifa tavsifi
Sizga butun sonlardan iborat nums massivi berilgan.
Massivdagi har bir nums[i] elementi uchun, massivda undan qat'iy kichik bo'lgan nechta raqam borligini hisoblang. Ya'ni, barcha j != i indekslar uchun nums[j] < nums[i] shartini qanoatlantiradigan j lar sonini hisoblashingiz kerak.
Natijani massiv ko'rinishida qaytaring.
Misol:
Input: nums = [8,1,2,2,3]
Output: [4,0,1,1,3]
Tushuntirish:
- 8 uchun 4 ta undan kichik son bor: 1, 2, 2, 3.
- 1 uchun undan kichik son yo'q.
- 2 uchun bitta kichik son bor: 1.
- 3 uchun 3 ta kichik son bor: 1, 2, 2.
How Many Numbers Are Smaller Than the Current Number
Oson10 daqiqa10 ball
📚 Misollar
Kiruvchi: nums = [8,1,2,2,3]
Chiquvchi: [4,0,1,1,3]
Kiruvchi: nums = [6,5,4,8]
Chiquvchi: [2,1,0,3]
func solve(_ nums: [Int]) -> [Int] {
// Kodingizni shu yerga yozing
return []
}
Run tugmasini bosing